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-6a^2+54=0
a = -6; b = 0; c = +54;
Δ = b2-4ac
Δ = 02-4·(-6)·54
Δ = 1296
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1296}=36$$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-36}{2*-6}=\frac{-36}{-12} =+3 $$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+36}{2*-6}=\frac{36}{-12} =-3 $
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